NCERT Solutions for Class 7 Mathematics Chapter 11 - Algebraic Expressions

Question 1:

Describe how the following expressions are obtained:
4x2 – 5x, 7xy + 5, x2y

Answer:

Question 2:

What are the terms in the following expressions? Show how the terms are formed. Draw a tree diagram for each expression.
8y + 3x2, 7mn – 4, 2x2y.

Answer:

We can represent the terms and factors of the terms of an expression by a tree diagram

Question 3:

Write three expressions each having 4 terms.

Answer:

Three expressions each having 4 terms are:
(i) 4x2 – 3y2 + 9x – 8y
(ii) 4x2 – 3xy + 4x + 13
(iii) 5x3 – 5x2 – 5x – 5

Question 4:

Identify the coefficients in the following terms:
4x – 3y, a + b + 5, 2y + 5, 2xy.

Answer:

In 4x – 3y,
4 is the coefficient of x and – 3 is the coefficient of y.
In a + b + 5
The coefficient of a and b is 1.
In 2y + 5, the coefficient of y is 2.
In 2xy, 2 is the coefficient of xy, x is the coefficient of 2y and y is the coefficient of 2x.

Question 5:

Group the like terms together from the following:
12x, 12, –25x, –25, –25y, 1, x, 12y, y

Answer:

Like terms are:
(i) 12x, –25x, x
(ii) 12, –25, 1
(iii) –25y, 12y, y

Question 6:

Classify the following expressions as a monomial, a binomial or a trinomial:
a, a + b, ab + a + b, ab + a + b – 5, xy, xy + 5, 5x2 – x + 2, 4pq – 3q + 5p, 7, 4m – 7n + 10, 4mn + 7.

Answer:

Monomials: a, xy, 7
Binomials: a + b, xy + 5, 4mn + 7
Trinomials: ab + a + b, 5x2 – x + 2, 4m – 4n + 10, 4pq – 3q + 5p

Question 7:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
Subtraction of z from y.

Answer:

y – z

Question 8:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
One half of the sum of numbers x and y.

Answer:

Question 9:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
The number z multiplied by itself.

Answer:

z2

Question 10:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
One fourth of the product of numbers p and q.

Answer:

Question 11:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
Numbers x and y both squared and added.

Answer:

x2 + y2

Question 12:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
Number 5 added to three times the product of numbers m and n.

Answer:

3mn + 5

Question 13:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
Product of numbers y and z subtracted from 10.

Answer:

10 – yz

Question 14:

Get the algebraic expression in the following cases using variables, constants and arithmatic operations.
Sum of numbers a and b subtracted from their product.

Answer:

ab – (a + b)

Question 15:

Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
x – 3

Answer:

Question 16:

Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
1 + x + x2

Answer:

Question 17:

Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
y – y3

Answer:

Question 18:

Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
5xy2 + 7x2y

Answer:

Question 19:

Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
– ab + 2b2 – 3a2

Answer:

Question 20:

Answer:

Question 21:

Answer:

Question 22:

Answer:

Question 23:

Answer:

Question 24:

Answer:

Question 25:

State whether a given pair of terms is of like or unlike terms:
1, 100

Answer:

1, 100 are like terms.

Question 26:

State whether a given pair of terms is of like or unlike terms:

Answer:

Question 27:

State whether a given pair of terms is of like or unlike terms:
– 29x, – 29y

Answer:

–29x, –29y are unlike terms.

Question 28:

State whether a given pair of terms is of like or unlike terms:
14xy, 42yx

Answer:

14xy, 42yx are like terms.

Question 29:

State whether a given pair of terms is of like or unlike terms:
4m2p, 4mp2

Answer:

4m2p, 4mp2 are unlike terms.

Question 30:

State whether a given pair of terms is of like or unlike terms:
12xz, 12x2z2

Answer:

12xz, 12x2z2 are unlike terms.

Question 31:

Identify like terms in the following:

Answer:

Question 32:

Identify like terms in the following:

Answer:

Question 33:

Think of at least two situations in which you need to form two algebraic expressions and add or subtract them.

Answer:

(i) The sides of a triangle are x cm, y cm and z cm respectively. Then the perimeter of the triangle is x + y + z.
(ii) Out of a class of 50 students, x students failed, then the number of students passed = 50 – x.

Question 34:

Add and subtract:
m – n, m + n

Answer:

m – n + m + n = 2m
m – n – (m + n) = m – n – m – n = – 2n

Question 35:

Add and subtract:
mn + 5 – 2, mn + 3

Answer:

(mn + 5 – 2) + (mn + 3) = mn + 5 – 2 + mn + 3
= 2mn + 6
(mn + 5 – 2) – (mn + 3) = mn + 5 – 2 – mn – 3 = 0

Question 36:

Simplify combining like terms:
21b – 32 + 7b – 20b

Answer:

21b – 32 + 7b – 20b
= 21b + 7b – 20b – 32 = (21 + 7 – 20) b – 32
= 8b – 32

Question 37:

Simplify combining like terms:
–z2 + 13z2 – 5z + 7z3 – 15z

Answer:

Question 38:

Simplify combining like terms:
p – (p – q) – q – (q – p)

Answer:

p – (p – q) – q – (q – p) = p – p + q – q – q + p
= p – p + p + q – q – q = p – q

Question 39:

Simplify combining like terms:
3a – 2b – ab – (a – b + ab) + 3ab + b – a

Answer:

3a – 2b – ab – (a – b + ab) + 3ab + b – a
= 3a – 2b – ab – a + b – ab + 3ab + b – a
= 3a – a – a – 2b + b + b – ab – ab + 3ab
= a + ab

Question 40:

Simplify combining like terms:

Answer:

Question 41:

Simplify combining like terms:
(3y2 + 5y2 – 4) – (8y – y2 – 4)

Answer:

Question 42:

Add:
3mn, – 5mn, 8mn, – 4mn

Answer:

(3mn) + (–5mn) + (8mn) + (–4mn)
= 3mn – 5mn + 8mn – 4mn
= 3mn + 8mn – 5mn – 4mn
= 11mn – 9mn = 2mn

Question 43:

Add:
t – 8tz, 3tz – z, z – t

Answer:

t – 8tz + 3tz – z + z – t
= t – t – 8tz + 3tz – z + z
= –5tz

Question 44:

Add:
–7mn + 5, 12mn + 2, 9mn – 8, – 2mn – 3

Answer:

(–7mn + 5) + (12mn + 2) + (9mn – 8) +
(–2mn – 3)
= –7mn + 5 + 12mn + 2 + 9mn – 8 – 2mn – 3
= –7mn + 12mn + 9mn – 2mn + 5 + 2 – 8 – 3
= 21mn – 9mn + 7 – 11 = 12mn – 4

Question 45:

Add:
a + b – 3, b – a + 3, a – b + 3

Answer:

(a + b – 3) + (b – a + 3) + (a – b + 3)
= a + b – 3 + b – a + 3 + a – b + 3
= a + b + b – a + a – b – 3 + 3 +3
= a + b + 3

Question 46:

Add:
14x + 10y – 12xy – 13, 18 – 7x – 10y
+ 8xy, 4xy

Answer:

(14x + 10y – 12xy – 13) +
(18 – 7x – 10y + 8xy) + 4xy
= 14x + 10y – 12xy – 13 + 18 – 7x – 10y + 8xy + 4xy
= (14 – 7)x + (10 – 10) y + (– 12 + 8 + 4) xy
+ (– 13 + 18) = 7x + 5

Question 47:

Add:
5m – 7n, 3n – 4m + 2, 2m – 3mn – 5

Answer:

(5m – 7n) + (3n – 4m + 2) + (2m – 3mn – 5)
= 5m – 7n + 3n – 4m + 2 + 2m – 3mn – 5
= 5m + 2m – 4m – 7n + 3n + 2 – 5 – 3mn
= 3m – 4n – 3 – 3mn

Question 48:

Add:

Answer:

Question 49:

Add:

Answer:

Question 50:

Add:
ab – 4a, 4b – ab, 4a – 4b

Answer:

(ab – 4a) + (4b – ab) + (4a – 4b)
= ab – 4a + 4b – ab + 4a – 4b
= ab – ab – 4a + 4a + 4b – 4b = 0

Question 51:

Add:

Answer:

Question 52:

Subtract:
–5y2 from y2

Answer:

Question 53:

Subtract:
6xy from – 12xy

Answer:

– 12xy – 6xy
= – 18xy

Question 54:

Subtract:
(a – b) from (a + b)

Answer:

(a + b) – (a – b)
= a + b – a + b = 2b

Question 55:

Subtract:
a(b – 5) from b(5 – a)

Answer:

b (5 – a) – a(b – 5)
= 5b – ab – ab + 5a
= 5a + 5b – 2ab

Question 56:

Subtract:
–m2 + 5mn from 4m2 – 3mn + 8

Answer:

Question 57:

Subtract:
–x2 + 10x – 5 from 5x – 10

Answer:

Question 58:

Subtract:

Answer:

Question 59:

Subtract:

Answer:

Question 60:

What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?

Answer:

Question 61:

What should be subtracted from 2a + 8b + 10 to get – 3a + 7b + 16?

Answer:

Question 62:

Answer:

Question 63:

From the sum of 3x – y + 11 and – y – 11 subtract 3x – y – 11.

Answer:

Question 64:

Answer:

Question 65:

If m = 2, find the value of
m – 2

Answer:

The value of (m – 2), when m = 2, is 0.

Question 66:

If m = 2, find the value of
3m – 5

Answer:

Put the value m = 2 in 3m – 5,
∴ 3m – 5 = 3 (2) – 5 = 6 – 5 = 1
The value of (3m – 5), when m = 2, is 1.

Question 67:

If m = 2, find the value of
9 – 5m

Answer:

Put the value m = 2 in 9 – 5m,
∴ 9 – 5m = 9 – (5 × 2)
= 9 – 10 = – 1
The value of (9 – 5m), when m = 2, is – 1.

Question 68:

If m = 2, find the value of
3m2 – 2m – 7

Answer:

Question 69:

Answer:

Question 70:

If p = – 2, find the value of
4p + 7

Answer:

Put p = (–2) in 4p + 7,
∴ 4p + 7 = 4 × (– 2) + 7 = – 8 + 7 = – 1
The value of (4p + 7), when p = –2, is –1.

Question 71:

If p = – 2, find the value of
–3p2 + 4p + 7

Answer:

Question 72:

If p = – 2, find the value of
–2p3 – 3p2 + 4p + 7

Answer:

Question 73:

Find the value of the following expression, when x = –1.
2x – 7

Answer:

Put x = –1 in 2x – 7,
2x – 7 = 2 (–1) – 7 = –2 – 7 = –9
∴ The value of (2x – 7), when x = –1, is –9.

Question 74:

Find the value of the following expression, when x = –1.
–x + 2

Answer:

Put x = –1 in –x + 2,
–x + 2 = –(–1) + 2 = 1 + 2 = 3
The value of (–x + 2), when x = –1, is 3.

Question 75:

Find the value of the following expression, when x = –1.
x2 + 2x + 1

Answer:

Put x = –1 in x2 + 2x + 1
x2 + 2x + 1 = (–1)2 + 2 (–1) + 1 = 1 – 2 + 1
= 2 – 2 = 0
The value of (x2 + 2x + 1), when x = –1, is 0.

Question 76:

Find the value of the following expression, when x = –1.
2x2 – x – 2

Answer:

Put x = –1, in 2x2 – x – 2.
2x2 – x – 2 = 2 (–1)2 –(–1) – 2
= 2 × 1 + 1 – 2 = 2 + 1 – 2 = 3 – 2 = 1
The value of (2x2 – x – 2), when x = –1, is 1.

Question 77:

If a = 2, b = –2, find the value of:
a2 + b2

Answer:

Question 78:

If a = 2, b = –2, find the value of:
a2 + ab + b2

Answer:

Question 79:

If a = 2, b = –2, find the value of:
a2 – b2

Answer:

Question 80:

When a = 0, b = –1, find the value of the given expressions:
2a + 2b

Answer:

Substituting a = 0, b = –1, in 2a + 2b, 2a + 2b = 2 (0) + 2 (–1)
= 0 – 2 = –2
∴ 2a + 2b = –2, when a = 0, b = –2.

Question 81:

When a = 0, b = –1, find the value of the given expressions:
2a2 + b2 + 1

Answer:

Question 82:

When a = 0, b = –1, find the value of the given expressions:
2a2b + 2ab2 + ab

Answer:

Question 83:

When a = 0, b = –1, find the value of the given expressions:
a2 + ab + 2.

Answer:

Question 84:

Simplify the expressions and find the value if x is equal to 2.
x + 7 + 4 (x – 5)

Answer:

Put x = 2 in the given expression, x + 7 + 4 (x – 5) = x + 7 + 4x – 20
= 5x – 13
= 5 (2) – 13 = 10 – 13 = –3
∴ x + 7 + 4 (x – 5) = –3, when x = 2.

Question 85:

Simplify the expressions and find the value if x is equal to 2.
3 (x + 2) + 5x – 7

Answer:

Put x = 2 in the given expression
3 (x + 2) + 5x – 7 = 3x + 6 + 5x – 7
= 8x – 1
= 8 × 2 – 1
= 16 – 1 = 15
∴ 3 (x + 2) + 5x – 7 = 15, when x = 2.

Question 86:

Simplify the expressions and find the value if x is equal to 2.
6x + 5 (x – 2)

Answer:

Put x = 2 in the given expression.
6x + 5 (x – 2) = 6x + 5x – 10
= 11x – 10
= 11 (2) – 10 = 22 – 10 = 12
∴ 6x + 5 (x – 2) = 12, when x = 2.

Question 87:

Simplify the expressions and find the value if x is equal to 2.
4 (2x – 1) + 3x + 11

Answer:

Put x = 2 in the given expression.
4 (2x – 1) + 3x + 11 = 8x – 4 + 3x + 11
= 11x + 7
= 11 × 2 + 7 = 22 + 7 = 29
∴ 4 (2x – 1) + 3x + 11 = 29, when x = 2.

Question 88:

Simplify these expressions and find their value if x = 3, a = –1, b = –2.
3x – 5 – x + 9

Answer:

3x – 5 – x + 9 = 3x – x – 5 + 9 = 2x + 4
Now, put x = 3 in 2x + 4,
2x + 4 = 2 × 3 + 4 = 6 + 4 = 10
∴ 3x – 5 – x + 9 = 10, when x = 3.

Question 89:

Simplify these expressions and find their value if x = 3, a = –1, b = –2.
2 – 8x + 4x + 4

Answer:

2 – 8x + 4x + 4 = 2 + 4 – 8x + 4x
= 6 – 4x
Now, put x = 3 in 6 – 4x
6 – 4x = 6 – 4 × 3 = 6 – 12 = –6
∴ 2 – 8x + 4x + 4 = – 6, when x = 3.

Question 90:

Simplify these expressions and find their value if x = 3, a = –1, b = –2.
3a + 5 – 8a + 1

Answer:

3a + 5 – 8a + 1 = 3a – 8a + 5 + 1
= –5a + 6
Now, put a = – 1 in – 5a + 6,
– 5a + 6 = – 5 (– 1) + 6 = 5 + 6 = 11
∴ 3a + 5 – 8a + 1 = 11, when a = – 1.

Question 91:

Simplify these expressions and find their value if x = 3, a = –1, b = –2.
10 – 3b – 4 – 5b

Answer:

10 – 3b – 4 – 5b = 10 – 4 – 3b – 5b = 6 – 8b
Now, put b = –2 in 6 – 8b
6 – 8b = 6 – 8 × (–2) = 6 + 16 = 22
∴ 10 – 3b – 4 – 5b = 22, when b = –2.

Question 92:

Simplify these expressions and find their value if x = 3, a = –1, b = –2.
2a – 2b – 4 – 5 + a

Answer:

2a – 2 b – 4 – 5 + a = 2 a + a – 2 b – 4 – 5
= 3a – 2b – 9
Now, put a = –1, b = –2 in 3a – 2b – 9,
3a – 2b – 9 = 3 (– 1) – 2 (–2) – 9 = – 3 + 4 – 9
= –12 + 4 = –8
∴ 2a – 2b – 4 – 5 + a = – 8, when a = –1, b = –2.

Question 93:

If z = 10, find the value of z3 – 3 (z – 10).

Answer:

Question 94:

If p = –10, find the value of p2 – 2p – 100.

Answer:

Question 95:

What should be the value of a if the value of 2x2 + x – a equals to 5, when x = 0 ?

Answer:

Here, 2x2 + x – a = 5
Putting x = 0, we get
2 (0)2 + (0) – a = 5
–a = 5
∴ a = –5

Question 96:

Simplify the expression and find its value when a = 5 and b = –3.
2 (a2 + ab) + 3 – ab.

Answer:

Question 97:

Answer:

Question 98:

Use the given algebraic expression to complete the table of number patterns (sequences).

Answer:

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